Monday, October 26, 2009

hw #3-6 Problem Set 3C

RECALL FROM OUR PREVIOUS ASSIGNMENT!!  
The TREMENDOUS CHALLENGE in this assignment is to NOT SIMPLY ANSWER the questions.  In each of the "story problem" questions, you are being asked to SET UP AN ALGEBRAIC EQUATION which can then be solved. 

SO, RESIST THE TEMPTATION TO JUST START DOING SOME MATH AND SOLVING EACH PROBLEM.  CHALLENGE YOURSELF TO SET UP AN ALGEBRAIC EQUATION.

8 comments:

  1. I do not get how to do number two

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  2. I do not get how to set the quation up

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  3. Jamie x is the number of quarters and then multiply it by 0.25. then add 0.1 times 2x then add 0.05 times the quantity x+2 equals 22.60

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  4. I don't understand problem 3

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  5. Never mind that last comment

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  6. To expand on #2 (quarters, dimes, nickels problem:

    Let's look at your definitions:

    q is the # of quarters
    2q is the number of dimes
    q+2 is the number of nickels

    Soooo, you had your choice of starter equations:

    Equation A:
    .25q + .10(2q) + .05(q+2) = 22.60

    or you could DISTRIBUTE a FACTOR of 100 to both sides and start like this:

    Equation B:
    25q + 10(2q) + 5(q+2) = 2260

    It is important to note that these are EQUIVALENT EQUATIONS, differing only by a factor of 100.

    Did this help? Let me know.

    Mr. C.

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  7. I do not understand how you set that equation up., though

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  8. Try looking at it from the perspective of “What adds up to $22.60?” We don’t want to sum the NUMBER of coins, we need to sum the VALUE of the coins.

    If you have 5 quarters, you have 5(.25) or $1.25, right?

    If you have 11 quarters, you have 11(.25) or $2.75, right?

    If you have n quarters, you have n*(.25) or .25n, right?

    Ca-peesh?? IT ALL ADDS UP!!

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