Did you check out the UNIT 3 SKILLS REVIEW on the MathChamber Unit 3 page??
If not, WHAT ARE YOU THINKING??
Wednesday, October 28, 2009
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This Blog exists for the collective benefit of all algebra students. All questions are welcome. The more specific your question (including your own attempts to answer it) the better.
EVEN MORE WELCOME ARE ANSWERS FROM FELLOW STUDENTS. BLOG ON!
For number seven i do not know -1/2p(p) is. is it -1/2p still
ReplyDeleteIn the expression -1/2(p - 7) you should DISTRIBUTE the -1/2 the way you would any other multiplier... e.g.
ReplyDelete-1/2(p - 7)
(-1/2)(p) - (-1/2)(7)
-1/2(p) - (-7/2)
-1/2(p) + 7/2
ca-peesh??
I don't see a -1/2p(p)...that would be -1/2(p^2) but I don't see where p is multiplied by p in this problem... unless I'm misunderstanding what you typed above?
Mr. C.
I got it but every single time I check it my answer is wrong! Here are my steps:
ReplyDelete3/8[13/12-8/1]+1/8[13/12]=-1/2[13/12-7/1]
13/32-3/1+19/96=-13/24--7/2
13/32-96/32+13/96=-13/24+7/2
-73/32+13/96=-13/24+98/24
-216/96+13/96=85/24
206/96=85/24
I know this can not be right! every time i do it the answer is different! please help
Well, your check step is providing you with valuable information... your solution is wrong... 13/12 is NOT the answer... so recap your solution steps and let's see where things went wrong.
ReplyDeletehiya.....if we study our problem sets, homework, and quiz. do ya think we are good to take the test
ReplyDeleteoh.....and i looked at the website...and i don't see anything/hints about the unit test 3 booster.
ReplyDeletewait the website says 13-14 but the answers give 15&16.
ReplyDelete-kevin
There is no Unit 3 Test Booster... at least not yet anyway. I'm banking that with this special group, no one will need it!!
ReplyDeleteAs for the 13,14,15,16 thing... I already told you guys I'm not very good with numbers. I figured an ambitious young maven like yourself (Kevin) would want to do some extra problems... am I right??
As for your question on hw, probelm sets, etc. the answer is YUP!
Mr. C.