Thursday, November 19, 2009

hw #4-6 & 4-7 Problem Set 4A & 4B

Do ALL of the problems in the packet!

15 comments:

  1. i don't know if anyone has noticed. either we are getting smarter.....or our computers are breaking down because the number of comments are falling at a fast rate.....

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  2. your first option is doubtful at best... I suspect the that the ever-villainous "schmeggegy" computer virus is at the root of the problem...

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  3. chills.....this is a job for......BLOB!!!!!!!! call 123-456-7890 you for free information guide!!! oh and is there a specific way our math binder should be organized? just wondering...

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  4. I do mine by homework, notes, and grades

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  5. However you organize is fine by me. Jamie's basically got it covered. My only addition will be the Algebra Toolkit, but that will be a composition book all by itself... separate from your notebook.

    Some students like to keep the Problem Sets in a separate section... I would prefer that you simply keep them in the hw section... but, again, however you organize is fine by me.

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  6. For number 7a, which was 7x+2y=10, I got
    y = -7/2x+5. Isn't y=5? my problem is then the slope is -7/2, where would this point be?

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  7. you need to simplify- 7/2 = 3.5 or 3 1/2. tah dah!!! the answer.

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  8. are labs considered homework or notes?

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  9. for y = -7/2x+5... now you have the equation in SLOPE-INTERCEPT form.

    The Y-INTERCEPT is 5; aka the ordered pair (0,5); you can graph that SINGLE POINT.

    The SLOPE is -7/2. You can USE the slope to graph other points (aka solutions on the line), by going up 7 and left 2, or down 7 and right 2... that's HOW you use -7/2 as a slope, capeesh?

    You COULD make a data table of values to prove that you could graph the line using either method.

    SLOPE-INTERCEPT form is a handy way to graph LINEAR EQUATIONS in the coordinate plane. It is a shortcut as opposed to using a data table of values every time you want to sketch a graph.

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  10. Butis that on tan axis?

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  11. Not sure I understand your question (typos aside :) )

    By definition, the y-intercept is where the line crosses the y-axis, so that one point is on the axis. There are many other solutions for the equation in the coordinate plane, hence the LINE formed by the LINEAR EQUATION.

    Try using the graphing calculator and see what it does.

    Mr. C.

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  12. Read the Coolmath and/or Purplemath entries listed by mathchamber 4.4 and I'll see you tomorrow in class.

    Good Night!

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